If \(3\sqrt{5} + \sqrt{125}= 17.88\) , then what will be the value of\(\sqrt{80} + 16\sqrt{5}\) ?
Answer: D
\(3\sqrt{5} + \sqrt{125}= 17.88\\ \Rightarrow 3\sqrt{5} + \sqrt{25 \times 5}= 17.88\\ \Rightarrow 3\sqrt{5} + 5\sqrt{5}= 17.88\\ \Rightarrow 8\sqrt{5}= 17.88\\ \Rightarrow \sqrt{5}= \dfrac{17.88}{8} = 2.235\\\\ \therefore \sqrt{80} + 16\sqrt{5}\\= \sqrt{16 \times 5} + 16\sqrt{5} \\ 4\sqrt{5} + 16\sqrt{5}\\= 20\sqrt{5}\\ = 20 \times 2.235\\ = 44.7\)