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Discussion

Find the median of the following frequency distribution:

Value (x)1012141618
Frequency (f)35642

  • A.12
  • B.13
  • C.14
  • D.15

Answer: C

First, find the total frequency (N) and the cumulative frequency (cf).

N = 3+5+6+4+2 = 20.

The median term is the average of the N/2 and (N/2)+1 terms, i.e., the 10th and 11th terms.

  • cf for 10 is 3.
  • cf for 12 is 3+5=8. (Terms 4 to 8 are 12)
  • cf for 14 is 8+6=14. (Terms 9 to 14 are 14)

Both the 10th and 11th terms fall in the group where the value is 14. Therefore, the median is 14.

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