Discussion
\(\frac{1}{1+a^{(n-m)}}+\frac{1}{1+a^{(m-n)}}=n^{?}\)
- A.0
- B.1/2
- C.1
- D.
Answer: B
\(\frac{1}{1+a^{(n-m)}}+\frac{1}{1+a^{(m-n)}} \)
\(= \frac{1}{(1+\frac{an}{am})}+\frac{1}{(1+\frac{am}{an})} \)
\(= \frac{am}{(am+an)}+\frac{an}{(am+an)} \)
\(= \frac{(am+an)}{(am+an)} \)
\(= 1\)
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