If \(m\) and \(n\) are whole numbers such that \(m^{n}=121\), the value of \((m-1)^{n+1}\) is:
Answer: D
We know that \(11^{2}=121\).
Putting m = 11 and n = 2, we get:
\((m-1)^{n+1}=(11-1)^{(2+1)}=10^{3}=1000\).