\((17)^{3.5}\times(17)^{?}=17^8\)
Answer: D
Let \((17)^{3.5}\times(17)^x=17^8\)
Then, \((17)^{3.5+x}=17^8\)
\(\therefore 3.5+x=8\)
\(\Rightarrow x=(8-3.5)\)
\(\Rightarrow x=4.5\)