\((2^{n+4}-2.2^{n})\div(2.2^{n+3})=2^{-3}\) is equal to:
Answer: D
\((2^{n+4}-2.2^{n})\div2.2^{n+3}+\frac{1}{2}^{3} \)
\(= \frac{7}{8}+\frac{1}{8} \)
\(= 1\)