If \(7^a = 16807\), then the value of \(7^{(a-3)}\) is:
Answer: A
\(7^a = 16807, \)
\(\Rightarrow 7^a = 7^5, a = 5\)
Therefore, \(7^{(a-3)} = 7^{(5-3)} = 7^2 = 49\)