Reema can complete a piece of work in 12 days while Seema can the same work in 18 days. If they both work together, then how many days will be required to finish the work?
Answer: B
| A's one day work = | 1 |
| 12 |
| B's one day work = | 1 |
| 18 |
| (A + B)'s one day work = | 1 | + | 1 | = | (18 + 12) | = | 30 | = | 1 |
| 12 | 18 | (12 x 18) | 216 | 7.2 |
Together, A & B will finish the work in 7.2 days.