If a tree casts a shadow of 10 meters when the angle of elevation of the sun is 60°, what is the height of the tree?
Answer: B
Let 'h' be the height of the tree and 's' be the length of the shadow. The angle of elevation is θ.
We have \(\tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{h}{s}\).
\(\tan 60° = \frac{h}{10}\)
Since \(\tan 60° = \sqrt{3}\), we have \(\sqrt{3} = \frac{h}{10}\).
h = 10√3 meters.