In a right-angled triangle ABC, right-angled at B, if \(\tan A = 1\), then the value of \(2 \sin A \cos A\) is:
Answer: B
If \(\tan A = 1\), then A = 45°.
The expression \(2 \sin A \cos A\) is the double angle identity for sine, \(\sin(2A)\).
So, we need to find \(\sin(2 \times 45°) = \sin(90°)\).
The value of \(\sin 90°\) is 1.