The value of \(9 \sec^2 A - 9 \tan^2 A\) is:
Answer: B
We can factor out the common term, 9.
Expression = \(9 (\sec^2 A - \tan^2 A)\).
Using the Pythagorean identity \(\sec^2 A - \tan^2 A = 1\), the expression becomes:
9 × 1 = 9.