From a point on the ground, 20 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?
Answer: B
Let h be the height and d be the distance from the foot.
\(\tan(\text{angle}) = \frac{\text{height}}{\text{distance}}\)
\(\tan 60° = \frac{h}{20}\)
\(\sqrt{3} = \frac{h}{20}\)
h = 20√3 meters.