If a pole 6 m high casts a shadow 2√3 m long on the ground, then the sun's angle of elevation is:
Answer: C
Let the angle of elevation be θ.
\(\tan \theta = \frac{\text{Height of pole}}{\text{Length of shadow}} = \frac{6}{2\sqrt{3}}\).
\(\tan \theta = \frac{3}{\sqrt{3}} = \sqrt{3}\).
The angle whose tangent is √3 is 60°.