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If a pole 6 m high casts a shadow 2√3 m long on the ground, then the sun's angle of elevation is:

  • A.30°
  • B.45°
  • C.60°
  • D.90°

Answer: C

Let the angle of elevation be θ.

\(\tan \theta = \frac{\text{Height of pole}}{\text{Length of shadow}} = \frac{6}{2\sqrt{3}}\).

\(\tan \theta = \frac{3}{\sqrt{3}} = \sqrt{3}\).

The angle whose tangent is √3 is 60°.

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