If the height of a vertical pole is equal to the length of its shadow on the ground, the angle of elevation of the sun is:
Answer: B
Let the height be h and the shadow length be s. We are given h = s.
The angle of elevation θ is given by \(\tan \theta = \frac{\text{height}}{\text{shadow}} = \frac{h}{s}\).
Since h = s, \(\tan \theta = 1\).
The angle whose tangent is 1 is 45°.