If a kite is flying at a height of 75m and is attached to a string making an angle of 60° with the ground, find the length of the string.
Answer: A
Let L be the length of the string (hypotenuse) and h be the height (opposite side).
\(\sin 60° = \frac{\text{height}}{\text{length}} = \frac{75}{L}\)
\(\frac{\sqrt{3}}{2} = \frac{75}{L}\)
\(L = \frac{75 \times 2}{\sqrt{3}} = \frac{150}{\sqrt{3}} = \frac{150\sqrt{3}}{3} = 50\sqrt{3}\) m.