Total number of questions : 20
Number of answered questions : 0
Number of unanswered questions : 20
Quantitative Aptitude [ Question No: 1 To 20 ] :
How many natural numbers between 17 and 80 are divisible by 6?
Your Answer : (Not Answered)
Correct Answer : B
The first multiple of 6 after 17 is 18 (6x3). The last multiple of 6 before 80 is 78 (6x13).
The numbers form an A.P.: 18, 24, ..., 78.
The number of terms can be found by the indices of the multiples: 3, 4, ..., 13.
Number of terms = (Last index - First index) + 1 = (13 - 3) + 1 = 11.
The Idempotent Law for set union states that:
Your Answer : (Not Answered)
Correct Answer : A
The Idempotent Law states that when an operation is applied to an element with itself, the result is the same element.
For set theory, this means:
1. A ∪ A = A (Idempotent Law of Union)
2. A ∩ A = A (Idempotent Law of Intersection)
What is the smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively?
Your Answer : (Not Answered)
Correct Answer : A
Here, the difference between the divisor and the remainder is constant in each case: \(20-14=6\), \(25-19=6\), \(35-29=6\), \(40-34=6\). The required number is of the form (LCM of divisors) - (constant difference). First, find the LCM of 20, 25, 35, 40. \(20 = 2^2 \times 5\), \(25=5^2\), \(35=5 \times 7\), \(40=2^3 \times 5\). LCM = \(2^3 \times 5^2 \times 7 = 8 \times 25 \times 7 = 200 \times 7 = 1400\). The required number is \(1400 - 6 = 1394\).
\(? \div 25 \div 12 = 248.64\)
Your Answer : (Not Answered)
Correct Answer : A
Let the missing number be x.
The equation is \(\frac{x}{25 \times 12} = 248.64\).
\(x = 248.64 \times 25 \times 12\).
\(x = 248.64 \times 300\).
\(x = 24864 \times 3 = 74592\).
The probability that a number selected at random from the first 50 natural numbers is a composite number is -.
Your Answer : (Not Answered)
Correct Answer : B
The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25.
What was the day of the week on 28th May, 2006?
Your Answer : (Not Answered)
Correct Answer : D
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Which of the following has its area and perimeter numerically equal?
Your Answer : (Not Answered)
Correct Answer : C
No answer description available for this question.
The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?
Your Answer : (Not Answered)
Correct Answer : B
4a = 68 => a = 17
17⊃2; – 8⊃2; = 15⊃2;
1/2 * 16 * 30 = 240
Sam invested Rs. 15000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be?
Your Answer : (Not Answered)
Correct Answer : C
P = Rs. 15000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year
Amount = [15000 * (1 + 5/100)⊃2;]
= (15000 * 21/20 * 21/20) = Rs. 16537.50
The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
Your Answer : (Not Answered)
Correct Answer : B
No answer description available for this question.
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:
Your Answer : (Not Answered)
Correct Answer : A
No answer description available for this question.
Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
Your Answer : (Not Answered)
Correct Answer : D
(x*5*1)/100 + [(2500 - x)*6*1]/100 = 140
X = 1000
How many kg of rice, of cost 9 Rs/kg must be mixed with 27 kg of rice of cost 7 Rs/kg get a gain of 10 % by selling the mixture at 9.24 Rs/kg?
Your Answer : (Not Answered)
Correct Answer : C
No answer description available for this question.
Rajesh has a container which has a mixture of wine and water in it. Wine and water are in the ratio 4:1. Rajesh spills some of the mixture by accident. He then replaces the spilled amount with water of same quantity. But now the wine to water ratio became 3:2. How much water did Rajesh add?
Your Answer : (Not Answered)
Correct Answer : C
No answer description available for this question.
A container has 40L milk. 4L milk is taken out and replaced with water, the process done three times. What is the amount of milk now left?
Your Answer : (Not Answered)
Correct Answer : C
In regard to the problem let after n times liquid in the container is x and liquid removed is y
=>Liquid in container= x
=>Liquid removed= y
After one trial, quantity of pure liquid= x- (1-y/x)
After n trials quantity of pure liquid = x - (1 -y/x)n
Therefore, Putting the values ( x = 40L y = 4L N=3) and solving
=> 40- (1-4/40)3
= 29.16L
In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
Your Answer : (Not Answered)
Correct Answer : C
No answer description available for this question.
A boats man can row in still water at speed of 7 km/hr. It takes 6 hours more to travel the same distance in upstream than in downstream if the speed of the river is 3 km/hr. what is the distance between the two destinations?
Your Answer : (Not Answered)
Correct Answer : B
x = 7 km/hr ; y = 3 km/hr
Ds = 10 km/hr ; Us = 4 km/hr
Distance (d) is same. Therefore, if time taken for downstream is t hours, the time for upstream is (t + 6) hours.
10*t = 4*(t + 6)
6t = 24 ; t = 4 hours
d = 10*4 = 40 km
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Your Answer : (Not Answered)
Correct Answer : B
Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m
a,b,c,d and e are five consecutive numbers in increasing order of size. Deleting one number from the set decreased the sum of the remaining numbers in the set by 20%.
Which one of the following numbers was deleted?
Your Answer : (Not Answered)
Correct Answer : C
No answer description available for this question.
How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
Your Answer : (Not Answered)
Correct Answer : A
\(132 = 4 \times 3 \times 11\)
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
\(264 \Rightarrow 11,3,4\)
\(396 \Rightarrow 11,3,4\)
\(462 \Rightarrow 11,3\)
\(792 \Rightarrow 11,3,4\)
\(968 \Rightarrow 11,4\)
\(2178 \Rightarrow 11,3\)
\(5184 \Rightarrow 3,4\)
\(6336 \Rightarrow 11,3,4\)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.