Two trains start at same time from two stations and proceed towards each other at the rate of 20 km/hr and 25 km/hr respectively. When they meet, it is found that one train has traveled 60 km more than the other. What is the distance between the two stations?
Answer: B
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Two trains A and B leave Kolkata for Sikkim at 8:00 pm and 8:30 pm respectively and run at 90 km/hr and 120 km/hr, respectively. At what distance from Kolkata, will the two trains meet?
Answer: B
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The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
Answer: B
Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
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Stations A and B are 220 km apart. A train leaves towards station B with speed of 40 km/hr at 10 pm. Another train leaves towards station A from station B with speed of 50 km/hr at 11 pm. At what time both trains meet?
Answer: C
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A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
Answer: B
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
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A train runs across a post in 15 seconds and across a platform of length 100m in 25 seconds. Determine the length of this train:
Answer: D
Let us assume for this question that the length of train is x metres and it is assumed to be running at the speed of y m/sec.
A pole is assumed as a point object.
=>Time taken by the train to pass the pole= x/y
=>15=x/y
=>y=x/15
Now, the train passes the platform which is 100 m in length in 25 seconds.
=>x+100/y=25
=>x+100/25=y
Equating speed generated from both cases:
x+100/25=x/15
Therefore x = 150 metres.
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A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: C
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Two trains each of which is 100 m long moving in opposite direction to one another cross each other taking 8 seconds. If speed of one train is twice the speed of other
train find the speed of the faster train.
Answer: C
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The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
Answer: C
Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: C
Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
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