In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
Answer: B
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Enter details here
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
Answer: B
No answer description available for this question.
Enter details here
There are two types of sugar. One is priced at Rs 62 per kg and the other is priced at Rs 72 per kg. If the two types are mixed together, the price of new mixture will be Rs 64.50 per kg. Find the ratio of the two types of sugar in this new mixture.
Answer: B
Cost Price of 1kg of Type 1 sugar = 6200 p.
Cost Price of 1kg of Type 2 sugar = 7200 p.
Mean Price of 1 kg of mixture = 6450 p.
According to the Rule of Alligation,
(Quantity of Cheaper):(Quantity of Dearer) = (CP of dearer – Mean Price):(Mean Price – CP of cheaper)
Therefore, the required ratio = (7200-6450):(6450-6200) = 750:250 = 3:1.
Enter details here
In what proportion must wheat at Rs. 15 per kg. be mixed with wheat at Rs. 18 per kg. So that the mixture will be worth Rs. 17 per kg. ?
Answer: B
No answer description available for this question.
Enter details here
Rice and wheat are in a mixture in the ratio 5:3. If 16 kg wheat is added to this mixture, the ratio of rice to wheat changes to 5:7. How much wheat is in new mixture?
Answer: B
No answer description available for this question.
Enter details here
A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
Answer: A
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Enter details here
A solution of honey and water is 28 liters, with honey and water in ratio 4:3. To this a 21 liter honey-water solution is added that has honey to water ratio as 2:1. Again a 51 liter honey-water solution that has honey to water ratio as 9:8 is added to this. After this 10 liter of the solution is replaced with pure honey. What is ratio of water to honey in the final mixture?
Answer: D
Total solution quantity 57+43 = 100
Out of 100 we are removing 10 liter (i.e. 10%)
so proportionately from honey we will remove = remove 5.7
& proportionately from water we will remove 10% remove = 4.3
Also, we add 10 liter pure honey
So now honey 57-5.7+10 = 61.3
& Water 43-4.3 = 38.7
water: Honey = 38.7 : 61.3 = 387:613
Enter details here
In a mixture of 90 L the ratio of acid and water is 2 : 1. If the ratio of acid and water is to be 1 : 2, then the amount of water (in liters) to be added to the mixture is?
Answer: C
So amount of acid = 2/ 2+1 × 90 = 60L
Amount of water = 90 - 60 = 30L
To make acid to water ratio = 1:2, we simply need
To make water double of acid.
By direct observation, we can say that we should
have 60L × 2 = 120L make the required ratio
We have 30L, we need (120-30) = 90L more water
Enter details here
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
Answer: B
No answer description available for this question.
Enter details here
All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Answer: D
B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.
Enter details here