Sunil started a juice (lemon syrup + water) counter. Initially he had 140 liter juice which had 30% water in it. He sold 20 liters of the juice. Then he added equal amount of lemon syrup and water. Now the ratio of water to lemon syrup became 1:2. How much water was added later on?
Answer: B
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A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: B
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A container has 40L milk. 4L milk is taken out and replaced with water, the process done three times. What is the amount of milk now left?
Answer: C
In regard to the problem let after n times liquid in the container is x and liquid removed is y
=>Liquid in container= x
=>Liquid removed= y
After one trial, quantity of pure liquid= x- (1-y/x)
After n trials quantity of pure liquid = x - (1 -y/x)n
Therefore, Putting the values ( x = 40L y = 4L N=3) and solving
=> 40- (1-4/40)3
= 29.16L
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Presently a mixture in a tub contains substances A and B in the ratio of 7:5. If 9 litres of this solution is drawn out and B is added to the mixture in certain quantity the resulting mixture becomes 7:9. How much litres of liquid A was kept in the tub initially?
Answer: D
Currently the mixture is in ratio of A/B: 7:5
=> This means fraction of A in the solution: 7/12
=> Fraction of B in the solvent: 5/12
=>New concentration of A= 7-(7/12)9
=>New concentration of B= 5-(5/12)9+x
=> (7-(7/12)9)/(5-(5/12)9+x) = 7/9
=>x=21
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A tank of 100 litres is filled with kerosene. Ram replaces 10% of kerosene with water and repeats this procedure 4 times. What is the amount of kerosene left in the tank?
Answer: B
As Ram replaces 10% of kerosene with water, the amount of kerosene left is 90%.
As the replacement is done four times,
After 1st replacement, kerosene left is : 0.9*100 = 90 litres
After 2nd replacement, kerosene left is : 0.9*90 = 81 litres
After 3rd replacement, kerosene left is : 0.9*81 = 72.9 litres
After 4th replacement, kerosene left is : 0.9*72.9 = 65.61 litres
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Find the ratio in which wheat of inferior quality (Rs.14/kg) be mixed with wheat of superior quality (Rs.28/kg) so that the shopkeeper gains Rs.2 by selling the resulting mixture at Rs.20/kg.
Answer: B
Let the resulting mixture be 1 kg, and x kg be the amount of wheat of inferior quality.
Therefore, (1-x)kg is the amount of wheat of superior quality.
As the shopkeeper gains Rs.2, the cost of the mixture is Rs.18
14 × x + 28 × (1-x) = 18
14x - 28x + 28 = 18
14x = 10
x = 5/7
(1 – x) = 2/7
x : (1-x) = 5/7 : 2/7
= 5 : 2
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A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Answer: D
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A mixture consists of some amount of sandalwood oil and 240 liters of water. It is priced at Rs. 275 per liter. Sandalwood oil is priced Rs. 325 per liter. How much oil is there in the mixture?
Answer: C
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A container has 40L milk. 4L milk is taken out and replaced with water, the process done three times. What is the amount of milk now left?
Answer: C
In regard to the problem let after n times liquid in the container is x and liquid removed is y
=>Liquid in container= x
=>Liquid removed= y
After one trial, quantity of pure liquid= x- (1-y/x)
After n trials quantity of pure liquid = x - (1 -y/x)n
Therefore, Putting the values ( x = 40L y = 4L N=3) and solving
=> 40- (1-4/40)3
= 29.16L
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Resultant price of mixture of golden rice is Rs. 480 per kg. This mixture is made from two varieties of golden rice which are having price of Rs. 420 per kg and Rs. 520 per kg. What should be ratio of quantities of both types of golden rice?
Answer: B
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