Command Line Arguments

What will be the output of the following C code (run without any command line arguments)?

#include 
    int main(int argc, char *argv[])
    {
        while (*argv  !=  NULL)
        printf("%s\n", *(argv++));
        return 0;
    }

What will be the output of the program (sample.c) given below if it is executed from the command line?
cmd> sample one two three

/* sample.c */
#include

int main(int argc, char *argv[])
{
    int i=0;
    i+=strlen(argv[1]);
    while(i>0)
    {
        printf("%c", argv[1][--i]);
    }
    return 0;
}

What will be the output of the following C code?

#include
main()
{
    typedef int a;
    a b=2, c=8, d;
    d=(b*2)/2+8;
    printf("%d",d);
}

What is the output of this C code?

#include 
    void foo(float *);
    int main()
    {
        int i = 10, *p = &i;
        foo(&i);
    }
    void foo(float *p)
    {
        printf("%f\n", *p);
    }

What is the output of this C code?

#include 
    int x = 0;
    void main()
    {
        int *ptr = &x;
        printf("%p\n", ptr);
        x++;
        printf("%p\n ", ptr);
    }

What will be the output of the following C code (run without any command line arguments)?

#include 
    int main(int argc, char *argv[])
    {
        while (argv != NULL)
        printf("%s\n",  *(argv++));
        return 0;
    }