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Series Completion

Important Instructions
Direction for [ Question No: 31 To 40 ] :

In each of the following questions, a number series is given with one term missing. Choose the correct alternative that will continue the same pattern.

31.

1, 6, 13, 22, 33, ?

Answer: D

The pattern is \(+5, +7, +9, +11,..\)

So the missing number \(= 33+13=46\).

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32.

1, 2, 3, 6, 9, 18, 34, ?

Answer: B

The numbers are alternately multiplied bt \(2\) and \(\frac{3}{2}\).
Thus \(1\times2=2,2\times \frac{3}{2}=3, 3\times 2=6,6\times \frac{3}{2}=9,..\)

\(\therefore\) Missing number = \(18 \times \frac{3}{2}=27\).

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33.

625, 5, 125, 25, 25, ?, 5

Answer: C

The given sequence is a combination of two series :
I. 625, 125, 25, 5 and II. 5, 25, ?
The pattern in I is ÷ 5, while that in II is x 5. So, missing term = 25 x 5 = 125.

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34.

1, 1, 2, 6, 24, ?, 720

Answer: D

The pattern is x 1, x 2, x 3, x 4,.....

So, missing term = 24 x 5 = 120.

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35.

16, 24, 36,… 81

Answer: B

Solution. (b) Previous number × = Next number

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36.

20, 20, 19, 16, 17, 13, 14, 11, ?, ?

Answer: A

Let the missing terms of the series be x1 and x2.
Thus, the sequence 20, 20, 19, 16, 17, 13, 14, 11, xv x2 is a combination of two series :
I. 20, 19, 17, 14, x1 and II. 20, 16, 13, 11, x2
The pattern in I is - 1, - 2, - 3,......So, missing term, x1 = 14 - 4 = 10.
The pattern in II is - 4, - 3, - 2,......So, missing term, x2 = 11 - 1 = 10.

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37.

2,2,5, 13,28,?

Answer: D

The pattern is + 0, + 3, + 8, + 15, ..... i.e. + (l2 - 1), + (22 - 1), + (32 - 1), + (42 - 1), .....
So, missing term = 28 + (52 - 1) = 28 + 24 = 52.

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38.

1, 4, 10, 22, 46, ?

Answer: C

Explanation:

The pattern is + 3, + 6, + 12, + 24,.....

So, missing term = 46 + 48 = 94.

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39.

120, 99, 80, 63, 48, ?

Answer: A

Explanation:The pattern is – 21, – 19, – 17, – 15,…..So, missing term = 48 – 13 = 35.

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40.

589654237, 89654237, 8965423, 965423, ?

Answer: D

Explanation:The digits are removed one by one from the beginning and the end in order alternatelyso as to obtain the subsequent terms of the series.

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