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Area

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31.

How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 30 m long and 16 1/2 m board?

Answer: A

30 * 33/2 = 5/2 * 2 * x => x = 99

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32.

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m,what is the area of the field?

Answer: B

No answer description available for this question.

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33.

What is the perimeter of a square field whose diagonal is 8√2?

Answer: B

No answer description available for this question.

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34.

The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?

Answer: C

(5 * 3.5)/2 = 8.75

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35.

A paper is in a square form whose one side is 20 cm. Two semi circles are drawn on its opposites as diameters. If these semi circles are cut down what is the area of the remaining paper?

Answer: A

No answer description available for this question.

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36.

The diffrence between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m,then its area is:

Answer: D

We have (l-b) = 23 and 2(l+b) = 206 or (l+b) = 103
Solving the two equatoins, we get l = 63 and b = 40
∴(l×b) = (63×40)m⊃2; = 2520 m⊃2;

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37.

A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?

Answer: A

Area = (l + b +2d) 2d

         = (75 + 55 +2.5 * 2) 2*2.5 => 675

675 * 2 = Rs.1350

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38.

The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?

Answer: D

26⊃2; – 10⊃2; = 24⊃2;

d1 = 20         d2 = 48

 

1/2 * 20 * 48 = 480

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39.

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

Answer: A

Let original length = x metres and original breadth = y metres
Original Area=xy m⊃2;
New Length =120100x=65x
New Breadth=120100y=65y
⇒New Area=65x * 65y   
⇒New Area=3625xy
Area Difference=3625xy−xy                            
=1125xy
Increase%=DifferenceActual * 100   
=11xy25 * 1xy * 100
=44%

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40.

The cross-section of a cannel is a trapezium in shape. If the cannel is 10 m wide at the top and 6 m wide at the bottom and the area of cross-section is 640 sq m, the depth of cannel is?

Answer: D

1/2 * d (10 + 6) = 640

d = 80

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