One can is completely filled and contains 100% water. Another similar can is completely filled with a solution of 50% wine and 50% water. When both the cans are emptied in a steel vessel, what will be ratio of water to wine in the vessel?
Answer: D
Since both cans are similar, let their capacity be 100 liters.
Can 1 has 100 liters water
And Can 2 has 50 liters wine and 50 liters of water
When mixed in steel vessel we get, 100+50 ISO liters water and SO liters wine
So water : wine3:1
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A jar is filled of liquid which is 3 parts water and 5 parts alcohol. How much of this mixture should be drawn out and replaced such that this mixture may contain half water and half alcohol?
Answer: B
Let the jar initially contain 8 liters of mixture:3 liters water and 5 liters alcohol
Let x liters of this mixture is drawn out and is replaced by x liters of water.
Amount of water now in the solution: 3-(3/8)x+x.
Amount of alcohol now in the solution: 5-(5/8)x
Desired ratio: 1/1
=>3-(3/8)x+x=5-(5/8)x
x=8/5 liters
%x=((8/5)/8) × 100=20%
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How much water must be added to a bucket which contains 40 liters of milk at the cost price of Rs.3.50 per liter so that the cost of milk reduces to Rs.2 per liter?
Answer: C
Total cost price =Rs(40 x 7/2) = Rs.140
Cost per litre =Rs.2,
Total quantity = 140/2 = 70 Litres.
Water to be added =(70-40) =30 Litres.
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Rajesh has a container which has a mixture of wine and water in it. Wine and water are in the ratio 4:1. Rajesh spills some of the mixture by accident. He then replaces the spilled amount with water of same quantity. But now the wine to water ratio became 3:2. How much water did Rajesh add?
Answer: C
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In what ratio must a grocer mix teas worth Rs.60 a kg and Rs.65 a kg.So that by selling the mixture at Rs. 68.20 a kg, He may gain 10%?
Answer: A
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In what ratio should a kind of sugar at 8.70 Rs/kg be mixed with another kind of sugar at 9.70 Rs/kg so that the mixture be worth 9 Rs/kg?
Answer: D
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One glass has juice and water in the ratio 5:2 while other glass has them in ratio 7:4, respectively. If both glasses poured in a vessel, then what will be final ratio of water to juice in the vessel?
Answer: D
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Two solutions S1 and S2 contain whisky and soda in the ratio 2 : 5 and 6 : 7 respectively. In what ratio these solutions be mixed to get a new solution S3, containing whisky and soda in the ratio 5 : 8 ?
Answer: A
Let the amount taken from S1 be 7x
And amount taken from S2 be 13y
(2x + 6y)/(5x + 7y) = 5/8
16x + 48y = 25x + 35y
9x = 13y
x/y = 13/9
Actual ratios of amounts
= 7x/13y
= (7/13) * (13/9)
= 7/9
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A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Answer: C
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Presently a mixture in a tub contains substances A and B in the ratio of 7:5. If 9 liters of this solution is drawn out and B is added to the mixture in certain quantity the resulting mixture becomes 7:9. How much liters of liquid A was kept in the tub initially?
Answer: D
Currently the mixture is in ratio of A/B: 7:5
=> This means fraction of A in the solution: 7/12
=> Fraction of B in the solvent: 5/12
=>New concentration of A= 7-(7/12)9
=>New concentration of B= 5-(5/12)9+x
=> (7-(7/12)9)/(5-(5/12)9+x) = 7/9
=>x=21
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