A circular wire of radius 21cm is cut and bent to form in the form of a rectangle whose sides are in the ratio of 6:5. Assuming, Π = 22/7, the area enclosed by the rectangle is
Answer: B
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Length of a rectangle is 12cm more than its breadth and it has a perimeter of 200cm. What will be diameter of a circle whose area matches the area of this rectangle?
Answer: B
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Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Answer: C
3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125
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Find perimeter of △LMN, if midpoints of its sides are joined to form △PQR. Also midpoints of △PQR are joined to get △CDE and CD=3, DE=8 and CE=4.
Answer: C
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If the length is increased by 25%, by what percent the width of a rectangle should be decreased so as to keep the area same.
Answer: B
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The perimeters of 5 squares are 24 cm, 32 cm, 40 cm, 76 cm and 80 cm respectively. The perimeter of another square equal in area to the sum of the area of these square is
Answer: C
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The length of each side of an equilateral triangle having an area of 4√3 cm⊃2; is?
Answer: D
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The length and breadth of a rectangle is increased by 10% and 25% respectively. What is the increase in the area?
Answer: B
100 * 100 = 10000
110 * 125 = 13750
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3750
10000 ------ 3750
100 ------- ? => 37.5%
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The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares .
Answer: A
We know perimeter of square = 4(side)
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = 10*10 - 8*8
= 36 cm
So side of third square = 6 (because area of square = side*side)
Perimeter=4*Side=4*6=24 cm
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In a Circle of Radius 5 cm if AB and AC are two equal chords of length 6cm each, then the length of chord BC is
Answer: D
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