The difference between a two-digit number and the number obtained by interchanging the digit is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1:2?
Answer: B
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let the ten's and unit's digits be \(2x\) and \(x\) respectively.
Then, \((10 \times 2x + x) - (10x + 2x) = 36\)
\(9x = 36\\
x = 4\)
Required difference
\(= (2x + x) - (2x - x)\\ = 2x\\ = 8\)
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