How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
Answer: B
Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
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A train is 31m long. It passes a platform which is 175 m long. What is the distance covered by the train in passing the platform?
Answer: A
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A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
Answer: B
Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10 = 89 sec.
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A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: A
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A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: B
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec
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Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
Answer: B
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A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Answer: A
Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
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A train passes a stationary pole in 8 seconds. The train also passes a 200 m long bridge in 28 seconds. What is the length and the speed of the train?
Answer: C
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Jammu Express is 1.2 km long and is running along the Kerala express at speed of 80km/hr. Kerala express is 2/3rd the length of Jammu express and runs at 60 km/hr. How much time will it take for Jammu express to overtake the Kerala express?
Answer: B
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A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: B
Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x meters.
Then, (x + 300)/36 = 15 ==> x + 300 = 540
x = 240 m.
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