Calendar
Important Instructions
Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?
Answer: A
Given that the month begins on a Friday and has 31 days
Sundays = 3rd, 10th, 17th, 24th, 31st
=> Total Sundays = 5
Every second & fourth Saturday is holiday.
2nd & 4th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 - (5 + 2) = 24 days.
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What was the day of the week on, 16th July, 1776?
Answer: A
16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
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On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006 ?
Answer: D
No answer description available for this question.
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What was the day of the week on 17th June, 1998?
Answer: A
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: C
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
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Which of the fallowing is not a leap year?
Answer: C
Leap year means the year that can be divisible by 4. From the above options 2009 is not divisible by 4. So it is not a leap year.
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1.12.91 is the first Tuesday. Which is the fourth Thursday of December 91 ?
Answer: B
Given that 2.12.91 is the first Tuesday
Hence we can assume that 4.12.91 is the first Thursday
If we add 7 days to 4.12.91, we will get second Thursday
If we add 14 days to 4.12.91, we will get third Thursday
If we add 21 days to 4.12.91, we will get fourth Thursday
=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.
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If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?
Answer: A
First,we count the number of odd days for the left over days in the given period.
Here,given period is 15.8.2012 to 11.6.2013
Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun
16 30 31 30 31 31 28 31 30 31 11(left days)
2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days
So,given day Thursday + 6 = Wednesday is the required result.
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Today is Monday. After 61 days, it will be:
Answer: B
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: C
On 31st December, 2005 it was Saturday.
Number of Odd days from the year 2006 to the year 2009 = (1+1+2+1)=5 days.
On 31st december 2009, It was Thursday
Thus, on 1st Jan, 2010 it is Friday.
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Topics
- Number System
- H.C.F. & L.C.M.
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