Calendar
Important Instructions
Which calendar was used again in the year 1856?
Answer: A
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828
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If today is Saturday, what will be the day 350 days from now ?
Answer: A
350 days = (350/7=50 weeks) i.e No odd days,
So it will be a Saturday.
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Suppose today is Friday, what day of the week will it be 65 days from now?
Answer: B
The day of the week repeats every 7 days.
Given today is Friday. Again Friday is repeated on the 7th day, 14th,... on 7 multiple days.
Hence, Friday is on the 63rd day, as 63 is multiple of 7.
Now, the required day of the week on the 65th day is Sunday.
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What was the day on 31st Dec,2011 ?
Answer: B
31st Dec, 2011 = (2010 years + Period from 1.1.2011 to 31.12.2011)
Odd days in 2000 years = 0
10 years has 2 leap years + 8 ordinary years.
Number of odd days in 10 years ( 2 x 2 + 8) = 5 odd days.
31st,Dec => complete year of 2011 (non-leap year) = 1 odd day.
Total number of odd days = (0 + 5 + 1) = 6.
Given day is saturday.
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If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Answer: A
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
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What is two weeks from today?
Answer: A
We know that the day repeats every 7 days, 14 days, 21 days,...
So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday.
Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.
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Today is Monday. After 61 days, it will be :
Answer: D
Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
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On what dates of April, 2001 did Wednesday fall?
Answer: D
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 
0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
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How much does a clock lose per day, if its hands coincide ever 65 minutes ?
Answer: C
55 min. spaces are covered in 60 min.
60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.
Loss in 65 min. = (720/11 - 65 ) = 5/11
Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
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The calendar of the year 1897 can be used again in the year?
Answer: C
Given Year is 1897, Which is a non leap year.
Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year.
Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903
Therfore, The calendar of the year 1897 can be used again in the year 1903
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Topics
- Number System
- H.C.F. & L.C.M.
- Decimal Fractions
- Simplification
- Square Roots & Cube Roots
- Average
- Problems on Numbers
- Problems on Ages
- Surds & Indices
- Operations on Numbers
- Percentage
- Profit & Loss
- Ratio & Proportion
- Partnership
- Chain Rule
- Time & Work
- Pipes & Cistern
- Time & Distance
- Problems on Trains
- Boats & Streams
- Alligation or Mixture
- Simple Interest
- Compound Interest
- Logarithms
- Area
- Volume & Surface Areas
- Mensuration
- Races & Games of Skill
- Calendar
- Clocks
- Stocks & Shares
- Permutations & Combinations
- Probability
- True Discount
- Banker’s Discount
- Heights & Distances
- Odd Man Out & Series
- Algebra
- Divisibility Rules & Remainder Theorem
- Factorials & Power Cycles
- Progressions (A.P., G.P., H.P.)
- Work & Wages
- Set Theory / Venn Diagrams
- Geometry (Lines, Angles, Triangles, Polygons)
- Coordinate Geometry
- Data Interpretation
- Trigonometry
- Statistics (Mean, Median, Mode)
- Arithmetic Operations