Calendar
Important Instructions
What will be the day of the week 15th August, 2010?
Answer: A
No answer description available for this question.
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What was the day on 9th May,2001?
Answer: A
9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day)= 3 odd day.
Total number of odd days = (0 + 0 + 3 ) = 3 odd day.
Given day is Wednesday.
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On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Answer: D
The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday
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How many days in 4 years?
Answer: A
Days in 4 years =>
Let the first year is Normal year i.e, its not Leap year. A Leap Years occurs once for every 4 years.
4 years => 365 + 365 + 365 + 366(Leap year)
4 years => 730 + 731 = 1461
Therefore, Number of Days in 4 Years = 1461 Days.
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How many leap years does 100 years have?
Answer: B
Given year is divided by 4, and the quotient gives the number of leap years.
Here, 100%4 = 25.
But, as 100 is not a leap year => 25 - 1= 24 leap years.
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How many seconds in 10 years?
Answer: B
We know that,
1 year = 365 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds.
Then, 1 year = 365 x 24 x 60 x 60 seconds.
= 8760 x 3600
1 year = 31536000 seconds.
Hence, 10 years = 31536000 x 10 = 315360000 seconds.
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What was the day of the week on 16th August, 1947?
Answer: C
15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )
Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)= [(11 x 2) + (36 x 1) ]odd days = 58 odd days = 2 odd days.
Jan Feb Mar Apr May Jun Jul Aug.
31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3,
Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days.
Hence, the required day was 'Saturday'.
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If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?
Answer: C
First,we count the number of odd days for the left over days in the given period.
Here,given period is 12.2.1986 to 1.1.1987
Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan
16 31 30 31 30 31 31 30 31 30 31 1 (left days)
2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day
So,given day Wednesday + 1 = Thursday is the required result
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What was the day on 25th Jan,1981?
Answer: C
25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)
Odd days in 1600 years = 0
Odd days in 300 years = 1
80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days
Jan = 25 days = (3 weeks + 4 days) = 4 odd days.
Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.
Given day is Sunday.
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The last day of a century cannot be
Answer: C
100 years contain 5 odd days.
Last day of 1st century is Friday.
200 years contain (5 x 2) 
3 odd days.
Last day of 2nd century is Wednesday.
300 years contain (5 x 3) = 15 1 odd day.
Last day of 3rd century is Monday.
400 years contain 0 odd day.
Last day of 4th century is Sunday.
This cycle is repeated.
Last day of a century cannot be Tuesday or Thursday or Saturday.
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Topics
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