If the third day of a month is Tuesday, which of the following would be the 25th day of that month?
Answer: B
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What day will be 61 days after today, if today is Monday?
Answer: C
The basic concept in a problem involving days is finding the number of odd days. In 61 days:
=> 7 x 8 + 5 = 5 odd days
=> Monday + 5 days = Saturday
Hence 61 days from today will be a Saturday.
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What will be the day on 18th Feb,2016?
Answer: B
18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)
Odd days in 1600 years = 0
Odd days in 400 years = 0
15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days
Jan Feb
(31 + 18 ) = 49 days
49 days = (7 weeks + 0 day)= 0 odd day.
Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.
Given day is Thursday
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On 17th March, 1997 Monday falls. What day of the week was it on 17th March, 1996?
Answer: C
The year 1996 is a leap year. So, it has 2 odd days. So, the day on 17th March, 1997 will be 2 days beyond the day on 17th March,1996.
Here 17th March, 1997 is Monday. So, 17th March, 1996 is Saturday.
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What was the day on 15th august 1947 ?
Answer: A
15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)
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In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?
Answer: D
From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
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If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ?
Answer: A
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 5th March, 2005 will be 1 day beyond the day on 5th March, 2004.
Given that, 5th March, 2005 is Monday.
5th March, 2004 is Sunday (1 day before to 5th March, 2005).
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April 19th, 1986 falls on which day?
Answer: A
19th April, 1986 = (1985 years + Period from 1.1.1986 to 19.4.1986)
Odd days in 1600 years = 0
Odd days in 300 years = 1
85 years has 21 leap years + 64 ordinary years.
Number of odd days in 85 years =( 21 x 2 + 64) = 1 odd day.
Jan. Feb. March April
(31 + 28 + 31 + 19) = 109 days
109 days = 15 weeks + 4 days= 4 odd day.
Total number of odd days = (1 + 0 + 1 + 4) = 6.
Given day is Saturday.
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The last day of a century cannot be
Answer: C
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Prove that any date in March of a year is the same day of the week corresponding date in November that year.
Answer: A
We will show that the number of odd days between last day of February and last day of October is zero. .
March April May June July Aug. Sept. Oct.
31 + 30 + 31 + 30 + 31 + 31 + 30 + 31
= 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0.
Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows
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