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Calendar

Important Instructions
51.

If July 9th,2013 falls on Sunday then Jan 7th,2014 falls on which day?

Answer: A

No answer description available for this question.

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52.

The calendar for the year 2007 will be the same for the year ?

Answer: D

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.

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53.

It was Sunday on Jan 1, 2006. Discover the week's day on Jan 1, 2010.

Answer: C

On 31st December,2005 it was Saturday.
Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days.

∴ On 31st December 2009 , it was Thursday.
In this way, on first jan, 2010 it is Friday.

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54.

How many days are there in k weeks k days ?

Answer: C

As we know that a week has 7 days,

k weeks k days = (7k + k) days = 8k days.

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55.

The maximum gap between two successive leap year is?

Answer: B

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

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56.

15th august 2010 was which day of the week?

Answer: D

15th August 2010 can be written as 2009 + days from 1st January 2010 to 15th August 2010.
=> Total number of odd days in 400 years = 0
Hence, total number of odd days in 2000 years = 0 (as 2000 is a perfect multiple of 400)
Odd in days in the period 2001-2009:
7 normal years + 2 leap yeas
=> (7*1) + (2*2) = 11
=> Odd days will be 11- (7*1) = 4
Days from January 1 to August 15 in 2010: 31+28+31+30+31+30+31+15
= 227 days.
= 32 weeks and 3 days, this gives additional 3 odd days.
=> Total odd days= 3+4=7
=> 7 odd days=1 week= 0 odd days
=> 0 odd days= Sunday
Thus, 15th August 2010 was a Sunday.

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57.

The calendar for the year 1993 will be same for the year

Answer: A

Given Year is 1993, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1993 + 11) = 2004, Which is a leap year. 

Step 2 : Add +6 to the given year (i.e 1993 + 6) = 1999

Therfore, The calendar for the year 1993 will be same for the year 1999

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58.

The year next to 2003 will have the same calendar as that of the year 2003?

Answer: B

Given year 2003, when divided by 4 leaves a remainder of 3.

NOTE: When remainder is 3, 11 is added to the given year to get the result.

So, 2003 + 11 = 2014

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59.

What was the week's day on sixteenth July, 1776?

Answer: B

16 July, 1776
= (1775 years + period from 1.1.1776 to 16.7.1776.
Checking of odd days.
No. of odd days in 1600 years =0
No. of odd days in 100 years = 5 

75 years= 18 jump years+57 conventional years
= (18*2+57*1) odd days = 93 odd days
= (13 weeks +2 days) = 2 odd days.
∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days

Jan + Feb. + March + April + May + June + July
31 +29 + 31 + 30 + 31 + 30 +16 = 198 days

198 days = (28 weeks+2 days) = 2 odd days
=Total no. of odd days = (0+2) = 2

Thus, the required day is Tuesday.

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60.

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

Answer: C

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

 On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

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