Calendar
Important Instructions
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010 ?
Answer: B
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 1st Jan 2006, it was Sunday.
Thus, On 1st Jan, 2010 it is Friday.
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The calendar of year 1989 was same as which year?
Answer: A
Given year 1989, when divided by 4 leaves a remainder of 1.
NOTE: When remainder is 1, 11 is subtracted to the given year to get the result.
So, 1989 - 11 = 1978
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5th January 2018 was a Friday. Which of the following years will also have 5th January on a Friday?
Answer: C
No answer description available for this question.
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What was the day of the week on 28th May, 2006?
Answer: D
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
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How many days are there in x weeks x days?
Answer: B
x weeks x days = (7x + x) days = 8x days.
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Which of the following years have 366 days?
Answer: A
When an year leaves a remainder 0 when divided by 4,then it is a leap year.
Here, 1984 divided by 4 leaves a remainder 0.
So, answer 1984 (366 days => leap year)
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January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
Answer: B
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday
1st day of the year 2008 will be 1 day beyond Monday
Hence, It will be Tuesday.
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What was the day of the week on 28th May, 2006?
Answer: A
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days
(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days.
Given day is Sunday
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The calendar for the year 2007 will be the same for the year:
Answer: D
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days 
0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
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Which of the following is not a leap year?
Answer: A
The century divisible by 400 is a leap year.
The year 700 is not a leap year.
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Topics
- Number System
- H.C.F. & L.C.M.
- Decimal Fractions
- Simplification
- Square Roots & Cube Roots
- Average
- Problems on Numbers
- Problems on Ages
- Surds & Indices
- Operations on Numbers
- Percentage
- Profit & Loss
- Ratio & Proportion
- Partnership
- Chain Rule
- Time & Work
- Pipes & Cistern
- Time & Distance
- Problems on Trains
- Boats & Streams
- Alligation or Mixture
- Simple Interest
- Compound Interest
- Logarithms
- Area
- Volume & Surface Areas
- Mensuration
- Races & Games of Skill
- Calendar
- Clocks
- Stocks & Shares
- Permutations & Combinations
- Probability
- True Discount
- Banker’s Discount
- Heights & Distances
- Odd Man Out & Series
- Algebra
- Divisibility Rules & Remainder Theorem
- Factorials & Power Cycles
- Progressions (A.P., G.P., H.P.)
- Work & Wages
- Set Theory / Venn Diagrams
- Geometry (Lines, Angles, Triangles, Polygons)
- Coordinate Geometry
- Data Interpretation
- Trigonometry
- Statistics (Mean, Median, Mode)
- Arithmetic Operations